increasing order of Oxidation state of S in S8, S2O8-2 , S2O3-2 , S4O6-2
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Answer:
S₈ , S₂O₃(2-),S₄O₆(2-) ,S₂O₈(2-)
Explanation:
Take oxidation state of oxygen as -2 and then calculate ny equating it to the net charge.
Ex: let x be sulphur's oxidation state
in S8 8x = 0
x = 0
In S2O8-2
2x-16 = -2
x =7
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