Physics, asked by shuklasahil2202, 4 months ago

induced potential difference of 30 V is produced in an inductor coil when the current in it is
increased from zero to 8.0 A in 0.3 second. Find the coefficient of self-induction of the coil

Answers

Answered by amoghnasa

1

E = -Ldi/dt

30 = -L (0-8)/0.3

L = 30*0.3/8

L = 1.11 H

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