Math, asked by akshi6614, 1 year ago

Inga is solving 2x2 + 12x – 3 = 0. Which steps could she use to solve the quadratic equation? Check all that apply. 2(x2 + 6x + 9) = 3 + 18 2(x2 + 6x) = –3 2(x2 + 6x) = 3 x + 3 = 2(x2 + 6x + 9) = –3 + 9 (x + 3)2 =

Answers

Answered by knjroopa
2

Answer:

Step-by-step explanation:

Given Inga is solving 2x2 + 12x – 3 = 0. Which steps could she use to solve the quadratic equation? Check all that apply.

2(x2 + 6x + 9) = 3 + 18

2(x2 + 6x) = –3

2(x2 + =6x) = 3

x + 3 = 21/2

2(x2 + 6x + 9) = –3 + 9

(x + 3)2 = 6/2

Now we have the equation that Inga s trying to solve is 2 x^2 + 12 x – 3 = 0

The steps are first, third and fourth

So now first one Inga can simplify as

2 (x^2 + 6 x + 9) = 3 + 18

Now again  second one Inga can solve as

2(x^2 + 6 x) = 3

Also Inga tries to solve third one as

X + 3 = 21/2

Answered by rhodemanmarlin
8

Answer:

2(x2 + 6x + 9) = 3 + 18

2(x2 + 6x) = 3

x + 3 = +/- square root of 21/2

Step-by-step explanation:

Because it is... :)

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