Question

inin the given figure 7 xy and MN are two parallel tangents to a circle with centre o and another tangent ab with point of contact intersecting xy at a and m n at b construct prove that angle aob equal to 90°​

Answer 1

Step-by-step explanation:

let us join the point o and c

in triangle OPA and triangle OCA

OP=OC

AP=AC

AO=AO

triangle OPA is congruent to OCA

POA=COA

similarly triangle OQB=OCB

triangle QOB = triangle COB

since POQ is diameter of the circle .it is a straight line.

triangle POA+COA+COB+QOB

2COA+2COB=180

COA+COB=90

therefore triangle AOB= 90