Math, asked by sandy89744, 2 months ago

Initial monthly salaries of Vikas and Rohan were in the ratio 6:7. The individual ratios between their present
and initial monthly salaries are 5:4 and 8:7 respectively. If the sum of their present monthly salaries is 3
62.000, find the initial monthly salary of Vikas.​

Answers

Answered by mathdude500
4

Appropriate Question :-

Initial monthly salaries of Vikas and Rohan were in the ratio 6:7. The individual ratios between their present and initial monthly salaries are 5:4 and 8:7 respectively. If the sum of their present monthly salaries is Rs 62, 000, find the initial monthly salary of Vikas.

Solution :-

It is given that

¤ The ratio between the present and initial monthly salary of Vikas is 5 : 4

☆ Let us assume that

  • Present salary of Vikas is 5x

  • Initial salary of Vikas is 4x.

Also,

It is given that

¤ The ratio between the present and initial monthly salary of Rohan is 8 : 7.

☆ Let us assume that

  • Present salary of Rohan is 8y

  • Initial salary of Rohan is 7y.

According to statement,

It is given that,

☆ Initial monthly salaries of Vikas and Rohan were in the ratio 6 : 7.

Therefore,

\rm :\longmapsto\:4x : 7y = 6 : 7

\rm :\longmapsto\:\dfrac{4x}{7y}  = \dfrac{6}{7}

\rm :\longmapsto\:\dfrac{4x}{y}  = \dfrac{6}{1}

\bf\implies \:x = \dfrac{3y}{2}  -  -  - (1)

Also,

According to statement,

☆ Sum of their present salary is Rs 62000.

\rm :\longmapsto\:5x + 8y = 62000

\rm :\longmapsto\:5 \times \dfrac{3y}{2}  + 8y = 62000

\rm :\longmapsto\:\dfrac{15y}{2}  + 8y = 62000

\rm :\longmapsto\:\dfrac{15y + 16y}{2}= 62000

\rm :\longmapsto\:\dfrac{31y}{2}= 62000

\rm :\longmapsto\:\dfrac{y}{2}= 2000

\bf\implies \:y = 4000 -  -  - (2)

☆ On substituting the value of y in equation (1), we get

\rm :\longmapsto\: \:x = \dfrac{3}{2} \times 2000

\bf\implies \:x = 3000

Hence,

Initial monthly salary of Vikas = 4x = 4 × 3000 = Rs 12000

Additional Information :-

\rm :\longmapsto\:If \: \dfrac{a}{b}  = \dfrac{c}{d} ,  \: then

\green{\boxed{ \bf{ \: \dfrac{a}{c}  = \dfrac{b}{d} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \{alternendo \} }}}

\green{\boxed{ \bf{ \: \dfrac{b}{a}  = \dfrac{d}{c} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \{invertendo \} }}}

\green{\boxed{ \bf{ \: \dfrac{a + b}{b}  = \dfrac{c + d}{d} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \{componendo \} }}}

\green{\boxed{ \bf{ \: \dfrac{a  -  b}{b}  = \dfrac{c  -  d}{d} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \{dividendo \} }}}

\green{\boxed{ \bf{ \: \dfrac{a}{b}  = \dfrac{c}{d} = \dfrac{a + c}{b + d}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \{addendo \} }}}

Answered by examreviewindia
1

Answer:

Rs 24000

Step-by-step explanation:

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