Question

Initial pressure of XY, is 600 mm Hg.
pressure at equilibrium is 800 mm Hg.
volume of system to remain constant, th
K is
(1) 50
(3) 20
(2) 100
(4) 400
... pressure of COCI. is 1000​

Answer 1

Answer:

XY

2

dissociates as:

XY

2

(g)⇌XY(g)+Y(g)

Initial pressure of XY

2

is 600 mm Hg. The total pressure at equilibrium is 800 mm Hg.

Let x mm Hg of XY

2

dissociates to reach equilibrium. x mm Hg of XY and x mm Hg of Y will be formed at equilibrium. 600−x mm Hg of XY

2

will be present at equilibrium.

Total pressure =(600−x)+x+x=600+x mm Hg

But total pressure =800 mm Hg

600+x=800 or x=200

Thus, the equilibrium pressures are

P

XY

2

=600−x=600−200=400 mm Hg

P

XY

=x=200 mm Hg

P

Y

=x=200 mm Hg

Assuming volume of system to remain constant, the value of K

p

=

P

XY

2

P

XY

P

Y

K

p

=

400

200×200

K

p

=100 mm