Initial velocity of a body is 10m/s and acceleration of a body is 5m/s square , then find out displacement travelled by the body in 5 th second.
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Given,
Initial velocity (u)= 10m/sec
Acceleration (a) = 5m/sec²
time (n) =5thsec
Now using second euqation of motion:-
Displacement (s) = u+ (1/2)a(2n-1)
→S= 10+ (1/2) 5*(2*5 -1)
→S= 10 + (1/2)5*9
→S= 10+ 45/2
→S= 32.5m.
.
Note:-
equations of motion are as follows:-
(I) v= u+at
(II) s= ut + (1/2)at²
(III) v² = u² + 2as.
Initial velocity (u)= 10m/sec
Acceleration (a) = 5m/sec²
time (n) =5thsec
Now using second euqation of motion:-
Displacement (s) = u+ (1/2)a(2n-1)
→S= 10+ (1/2) 5*(2*5 -1)
→S= 10 + (1/2)5*9
→S= 10+ 45/2
→S= 32.5m.
.
Note:-
equations of motion are as follows:-
(I) v= u+at
(II) s= ut + (1/2)at²
(III) v² = u² + 2as.
Harishankar171299:
112.5
galat hai bhai
answe is 32.5
How 32.5
let me correct it
nope its 32.5
ok
then it is difference of 5 sec or 5th second
ok guys
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