Math, asked by pooja351, 1 year ago

Find the value of 4sin square 60degree-cos degree 45degree *tan square 30 degree +sinsquare 0degree

Answers

Answered by chhajedchirag1p32bb2
0

4 \sin(60) {}^{2}   -  \cos(45 {}^{} ) {}^{2}  \times  \tan(30) {}^{2}  +  \sin(0) {}^{2}  \\ 4 \times ( \frac{ \sqrt{3} }{2} ) {}^{2} - ( \frac{1}{ \sqrt{2} } ) {}^{2}  \times ( \frac{1}{ \sqrt{3} }) - 0 {}^{2} \\ 4 \times  \frac{3}{4} -  \frac{1}{2} \times  \frac{1}{3}   - 0 \\ 3 -  \frac{1}{2}   \times  \frac{1}{3}  \\ 3 -  \frac{1}{6} \\  \frac{3 \times 6}{1 \times 6} \\  \frac{18}{6}   -  \frac{1}{6} \\  \frac{17}{6} \\
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