Question

Initial velocity of projection of a projectile is

ˆ ˆ u 6i + 8j m /s

&

. The angle of projection is :​

Answer 1

Answer: 53 degrees

Explanation:

Velocity of projectile =√6^2+8^2 = √100= 10 m/s

Angle of projectile θ = tan^-1 8/6= 53degrees