Question

initially a body is at rest if its acceleration is 5 metre per second square then the distance travelled in the eighteenth second is

Answer 1

u = 0 ms
a = 5 ms^-2
t = 18s

By first equation of motion,

v = u + at = 0 + (5)(18) = 0 + 90 = 90 ms
v = 90 ms

By second equation of motion,

s = ut + (1/2)(a)(t)(t) = (0)(18) + (1/2)(5)(18)(18) = 0 + 45(18) = 45(18) = 810 m

Thus, the distance travelled in the 18th second is 810 meters.

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Answer 2

Explanation:

here in this question I have use the second equation that is s is equals to UT plus half a t square in which I have put it 18 - 1 and from that I get got answer 87.5 hope this helps you bro thanks a lot for asking this question