Question

Initially a car a is 10.5 M ahead of car be both start moving at time t is equal to zero in the same direction along a straight line the velocity time graph of to configure the time when the car will catch the car I will be

Answer 1

Let car B will catch car A after travelling a distance of 10.5 + x... so from que time taken by both the car to meet each other will be same.Therefore the equation will be vt+10.5=1/2at^2 where v=10m/s and a=1m/s^2

now you can solve it

hope it will help you

Answer 2

Answer:21 sec, the question generally comes with a graph.