Question

Initially a car is moving with speed of 20 ms- and
covers a distance of 100 m before it comes to rest.
On making the initial speed of car 40 ms-
keeping the acceleration same, the distance
travelled by car before it comes to rest is​

Answer 1

Answer:

800m

Explanation:

0²=20²+2aS

a=-400/2S

a=-400/200

a=-2m/s²

Acceleration is same, now u=40m/s

0²=40²+2aS¹

S¹=-1600÷(2×-2)

S¹=800m