Initially, you are at the position x = 1.3 m and your friend is at the position x = 11.2 m. You both walk towards each other till you meet, but you walk double the distance that your friend walks. Where do you both meet?
Answers
Both meet at 7.9 m
Step-by-step explanation:
you are at the position x = 1.3 m
friend is at the position x = 11.2
you walk double the distance that your friend walks.
Let say ur friend walk = d m
then you walk = 2d m
1.3 + 2d = 11.2 - d
=> 3d = 9.9
=> d = 3.3 m
1.3 + 2(3.3) = 7.9 or 11.2 - 3.3 = 7.9
Both meet at 7.9 m
you Initial you walked meet friend walked initial ( friend)
1.3 ------------ (6.6) -------------- 7.9 -------(3.3) ------- 11.2
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Answer:
Step-by-step explanation:
Let's call the distance you walk "d", so your friend walks a distance of "d/2". Since you both walk towards each other, the total distance between you will decrease by the sum of the distances you each walk. The distance between you initially is 11.2 m - 1.3 m = 9.9 m. So, we can set up the following equation:
9.9 m - (d + d/2) = 0
Simplifying this equation, we get:
9.9 m - 1.5d = 0
Solving for "d", we get:
d = (9.9 m) / 1.5 = 6.6 m
This means that you walk a distance of 6.6 m towards your friend, while your friend walks a distance of 3.3 m towards you. So, you both meet at a distance of 1.3 m + 6.6 m = 7.9 m from your initial position, or a distance of 11.2 m - 6.6 m = 4.6 m from your friend's initial position. Therefore, you both meet at the point (x = 7.9 m).
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