Question

Initially, you are at the position x = 1.3 m and your friend is at the position x = 11.2 m. You both walk towards each other till you meet, but you walk double the distance that your friend walks. Where do you both meet?

Answer 1

Both meet at  7.9  m

Step-by-step explanation:

you are at the position x = 1.3 m

friend is at the position x = 11.2  

you walk double the distance that your friend walks.

Let say ur friend walk = d  m

then you walk = 2d m

1.3  + 2d  = 11.2  - d

=> 3d = 9.9

=> d = 3.3 m

1.3 + 2(3.3)  =  7.9    or 11.2 - 3.3  = 7.9

Both meet at  7.9  m

you Initial      you walked        meet    friend walked  initial ( friend)

  1.3 ------------ (6.6)   -------------- 7.9    -------(3.3)  -------   11.2

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Answer 2

Answer:

Step-by-step explanation:

Let's call the distance you walk "d", so your friend walks a distance of "d/2". Since you both walk towards each other, the total distance between you will decrease by the sum of the distances you each walk. The distance between you initially is 11.2 m - 1.3 m = 9.9 m. So, we can set up the following equation:

9.9 m - (d + d/2) = 0

Simplifying this equation, we get:

9.9 m - 1.5d = 0

Solving for "d", we get:

d = (9.9 m) / 1.5 = 6.6 m

This means that you walk a distance of 6.6 m towards your friend, while your friend walks a distance of 3.3 m towards you. So, you both meet at a distance of 1.3 m + 6.6 m = 7.9 m from your initial position, or a distance of 11.2 m - 6.6 m = 4.6 m from your friend's initial position. Therefore, you both meet at the point (x = 7.9 m).


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