Initialy sphere A has charge of -50e and sphere B has
charge of +20e. The spheres are made of conducting
material and are
identical in size. If the sphere are
then touch, what is the resulting charge on sphere A?
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Answer:
The force exerted by the charges is given as follows.
F
1
=
4πε
0
1
r
2
q
1
q
2
.
F
2
=
k
1
4πε
0
1
r
2
q
1
q
2
.
Therefore,
F
2
F
1
=
k
1
orF
2
=
k
F
1
.
That is,
F
2
=
2
F
1
ask=2(given).
Hence, the force is F/2.
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