inorganic and radioactive substances which lead 2 land degradation
Answers
It is mainly pollution.
Examples of inorganic compounds are mainly polythene bags.
They do not decompose and thus when disposed in the environment, they pollute the soil affecting soil productivity.
On the other hand, radioactive degradation involves disposing radioactive wastes into the environment.
They mainly result from producing power by nuclear reaction.
Example of waste from this is Uranium which has a longer half life thus degrading the environment for a longer period.
Explanation:
Answer: The correct answer is Option B.
Explanation:
To calculate the number of moles, we use the equation:
\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}Number of moles=
Molar mass
Given mass
.....(1)
For Option A:
Given mass of methane = 16 g
Molar mass of methane = 16 g/mol
Putting values in equation 1, we get:
\text{Moles of methane}=\frac{16g}{16g/mol}=1molMoles of methane=
16g/mol
16g
=1mol
1 mole of methane compound is formed by 1 mole of carbon and 4 moles of hydrogen atoms.
According to mole concept:
1 mole of a gas contains 6.022\times 10^{23}6.022×10
23
number of atoms.
So, 1 mole of methane compound will have 4\times 1\times 6.022\times 10^{23}=24.088\times 10^{23}4×1×6.022×10
23
=24.088×10
23
number of hydrogen atoms.
Number of hydrogen atoms = 24.088\times 10^{23}24.088×10
23
For Option B:
Given mass of C_6H_4C
6
H
4
= 31.2 g
Molar mass of C_6H_4C
6
H
4
= 76 g/mol
Putting values in equation 1, we get:
\text{Moles of }C_6H_4=\frac{31.2g}{76g/mol}=0.41molMoles of C
6
H
4
=
76g/mol
31.2g
=0.41mol
1 mole of C_6H_4C
6
H
4
compound is formed by 6 moles of carbon and 4 moles of hydrogen atoms.
According to mole concept:
1 mole of a gas contains 6.022\times 10^{23}6.022×10
23
number of atoms.
So, 0.41 mole of C_6H_4C
6
H
4
compound will have 4\times 0.41\times 6.022\times 10^{23}=9.876\times 10^{23}4×0.41×6.022×10
23
=9.876×10
23
number of hydrogen atoms.
Number of hydrogen atoms = 9.876\times 10^{23}9.876×10
23
For Option C:
Given mass of C_{12}H_{22}O_{11}C
12
H
22
O
11
= 34.2 g
Molar mass of C_{12}H_{22}O_{11}C
12
H
22
O
11
= 342.3 g/mol
Putting values in equation 1, we get:
\text{Moles of }C_{12}H_{22}O_{11}=\frac{34.2g}{342.3g/mol}=0.099molMoles of C
12
H
22
O
11
=
342.3g/mol
34.2g
=0.099mol
1 mole of C_{12}H_{22}O_{11}C
12
H
22
O
11
compound is formed by 12 moles of carbon, 22 moles of hydrogen atoms and 11 moles of oxygen atoms.
According to mole concept:
1 mole of a gas contains 6.022\times 10^{23}6.022×10
23
number of atoms.
So, 0.099 mole of C_{12}H_{22}O_{11}C
12
H
22
O
11
compound will have 22\times 0.099\times 6.022\times 10^{23}=13.116\times 10^{23}22×0.099×6.022×10
23
=13.116×10
23
number of hydrogen atoms.
Number of hydrogen atoms = 13.116\times 10^{23}13.116×10
23
For Option D:
Given mass of C_{6}H_{12}O_{6}C
6
H
12
O
6
= 36 g
Molar mass of C_{6}H_{12}O_{6}C
6
H
12
O
6
= 180.156 g/mol
Putting values in equation 1, we get:
\text{Moles of }C_{6}H_{12}O_{6}=\frac{36g}{180.156g/mol}=0.199molMoles of C
6
H
12
O
6
=
180.156g/mol
36g
=0.199mol
1 mole of C_{6}H_{12}O_{6}C
6
H
12
O
6
compound is formed by 6 moles of carbon, 12 moles of hydrogen atoms and 6 moles of oxygen atoms.
According to mole concept:
1 mole of a gas contains 6.022\times 10^{23}6.022×10
23
number of atoms.
So, 0.199 mole of C_{6}H_{12}O_{6}C
6
H
12
O
6
compound will have 12\times 0.199\times 6.022\times 10^{23}=14.38\times 10^{23}12×0.199×6.022×10
23
=14.38×10
23
number of hydrogen atoms.
Number of hydrogen atoms = 14.38\times 10^{23}14.38×10
23
Hence, the correct answer is Option B.