Inorganic compound contains 4. 07 % hydrogen 20 4. 2 % carbon and 71. 6 5% chlorine the vapour density of the compound is 40 9. 48 find its molecular formula
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Number of Moles of H = 4.07/1 = 4 (almost)
Number of Moles of C = 24.27/12 = 2(almost)
Number of Moles of Cl = 71/35.5 = 2(almost)
Ratio
C:H:Cl = 2:4:2 = 1:2:1
Empirical Formula = CH2Cl
Empirical Formula Mass =12+2+35 = 49
n = 98.96/46 = 2(almost)
Molecular formula = n x empirical formula = C2H5Cl2
Number of Moles of C = 24.27/12 = 2(almost)
Number of Moles of Cl = 71/35.5 = 2(almost)
Ratio
C:H:Cl = 2:4:2 = 1:2:1
Empirical Formula = CH2Cl
Empirical Formula Mass =12+2+35 = 49
n = 98.96/46 = 2(almost)
Molecular formula = n x empirical formula = C2H5Cl2
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