inorganic compound contains 80% br and the mass of agbr formed from the one gram of compound in carius method
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Molar mass of AgBr = 108 + 80 = 188 g mol-1
188 g AgBr contains 80 g bromine
0.12 g AgBr contains= 80 X 0.12/188 g bromine
Percentage of bromine=80 X0.12 X100/188 X 0.15
= 34.04%
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