Question

input a three digit number and check whether the middle digit is odd or even?(plz explain In details) ​

Answer 1

Language:

Python

Logic:

Let the number be abc (a three digit number).

First thing you need to do is retrieve the middle number and for that we'll be using

a)% (modulus operator) which return the remainder

b) // opertaor to get the quotient.

first abc%100 = bc (eg. 125 on dividing with 100 returns remainder 25)

now bc//10 =  b (eg. 25 on being divided by 10 returns quotient 2)

Now to check if the number is even or odd use % with 2 eg. 2%2 is the output value is o ( i.e reminder is 0) the number was even and if not it was odd (Eg 5%2=1 hence odd).

Program:

a=int(input("Enter a 3-digit number: "))

if (a%100//10)%2==0:

   print(a%100//10,"is even.")

else:

   print(a%100//10,"is odd.")

Output:

Enter a 3-digit number: 125

2 is even.

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