Insert 5 number b/w 8 and 26 such that the resulting sequence is an AP.
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Let A1,A2,A3,A4,A5 be five numbers between 8 and 26 such that 8,A1,A2,A3,A4,A5,A26 are in AP.
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Assume that A1, A2, A3, A4, and A5 are the five numbers between 8 and 26, such that the sequence of an A.P becomes 8, A1, A2, A3, A4, A5, 26
Here, a= 8, l =26, n= 5
Therefore, 26= 8+(7-1)d
Hence it becomes,
Hence, the required five numbers between the number 8 and 26 are 11, 14, 17, 20, 23
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