Math, asked by astha735, 10 months ago

Insert 5 number b/w 8 and 26 such that the resulting sequence is an AP.

Answers

Answered by ANGEL123401
4

Let A1,A2,A3,A4,A5 be five numbers between 8 and 26 such that 8,A1,A2,A3,A4,A5,A26 are in AP.

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Answered by Anonymous
61

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Assume that A1, A2, A3, A4, and A5 are the five numbers between 8 and 26, such that the sequence of an A.P becomes 8, A1, A2, A3, A4, A5, 26

Here, a= 8, l =26, n= 5

Therefore, 26= 8+(7-1)d

Hence it becomes,

 \tt 26 = 8+6d

 \tt 6d = 26-8 = 18

 \tt 6d= 18

 \tt d = 3

 \tt A1= a+d = 8+ 3 =11

 \tt A2= a+2d = 8+ 2(3) =8+6 = 14

 \tt A3= a+3d = 8+ 3(3) =8+9 = 17

 \tt A4= a+4d = 8+ 4(3) =8+12 = 20

 \tt A5= a+5d = 8+ 5(3) =8+15 = 23

Hence, the required five numbers between the number 8 and 26 are 11, 14, 17, 20, 23

Hope it's Helpful....:)

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