Math, asked by arav26, 1 year ago

insert 7 am between 2 and 17

Answers

Answered by hukam0685
0

Step-by-step explanation:

Given:2 and 17

To find: Insert 7 A.M.

Solution:

To insert 7 arithmetic mean,so that resultant sequence will be A.P.

we have to find common difference

Let seven A.M.'s are

a1,a2,a3... a7

So,

2,a1,a2,a3... a7, 17

17 is 9th term of the sequence

Apply general term formula

a_n = a + (n - 1)d \\  \\ 17 = 2 + 8d \\  \\ 17 - 2 = 8d \\  \\ d =  \frac{15}{8}  \\  \\d =  1.875 \\  \\

So,

the numbers are

a1=2+1.875=3.875

a2=2+2×1.875=5.75

a3=2+3×1.875=7.625

a4=2+4×1.875=9.5

a5=2+5×1.875=11.375

a6=2+6×1.875=13.25

a7=2+7×1.875=15.125

Thus,Seven A.M's are (3.875, 5.75, 7.625, 9.5, 11.375, 13.25, 15.125) inserted in between 2 and 17

Hope it helps you.

To learn more on brainly:

1)Find 14 A. M's between 5 and 8 and hence show that their sum is 14 times the AM.

between 5 and 8.

https://brainly.in/question/12958973

2)insert 4 Arithmetic mean between 5 and 20

https://brainly.in/question/2879345

Answered by charisma47
0

Answer:

Seven A.M's are (3.875, 5.75, 7.625, 9.5, 11.375, 13.25, 15.125) inserted in between 2 and 17

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