Math, asked by satender74, 1 year ago

insert five numbers between 8 snd 26 such that the resulting sequence in an AP ye question agar paper me aaye to kaise likhoge​

Answers

Answered by drithvik1
0

a5=a+4d=20

A6=a+5d=23

therefore

the 5 no. between 8 and 26 that form a.p is 11,14,17,20,23

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Answered by Anonymous
52

{\huge {\boxed{\bold{\boxed{\mathfrak{\color{red}{Answer}}}}}}}

Assume that A1, A2, A3, A4, and A5 are the five numbers between 8 and 26, such that the sequence of an A.P becomes 8, A1, A2, A3, A4, A5, 26

Here, a= 8, l =26, n= 5

Therefore, 26= 8+(7-1)d

Hence it becomes,

 \tt 26 = 8+6d

 \tt 6d = 26-8 = 18

 \tt 6d= 18

 \tt d = 3

 \tt A1= a+d = 8+ 3 =11

 \tt A2= a+2d = 8+ 2(3) =8+6 = 14

 \tt A3= a+3d = 8+ 3(3) =8+9 = 17

 \tt A4= a+4d = 8+ 4(3) =8+12 = 20

 \tt A5= a+5d = 8+ 5(3) =8+15 = 23

Hence, the required five numbers between the number 8 and 26 are 11, 14, 17, 20, 23

Hope it's Helpful....:)

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