Question

Insert p A.M's between 1 and p2.​

Answer 1

Answer:

(p+2)/(p+1) ,  (p+3)/(p+1) , ...................................................(2p + 1)/(p+1)

Step-by-step explanation:

insert p  AM between  1 & 2

So total number will be p + 2

First number = 1

Last number = 2

2 = 1 + (p+2 - 1)d

=> d = 1/(p + 1)

1   ,  1 + 1/(p + 1)  ,  1  +  2/(p + 1)  ,..................................................1 + p/(p+1)  , 2

1 , (p+2)/(p+1) , (p+3)/(p+1) , ...................................................(2p + 1)/(p+1)  , 2

Inserted Mean

= (p+2)/(p+1) ,  (p+3)/(p+1) , ...................................................(2p + 1)/(p+1)