Question

Insert two numbers between 576 and 9 so that the
resulting sequence is a G.P.​

Answer 1

Answer:

Step-by-step explanation:

if the numbers are to be in GP then their common ratio must be same for any two numbers

576,x,y,9

x/576=9/y=y/x

y/x=9/y

y^2=9x

y=3sqrt(x)

x/576=9/3sqrt(x)

x/576=3/sqrt(x)

x*x^(1/2)=576*3

x^(3/2)=1728

x=(1728)^(2/3)

=144

substitue in y=3sqrt(144)=3*12=36

Answer 2

Answer:

Step-by-step explanation:

a=9

ar^n-1=576

n=4

ar³=576

9r³=576

r³=64

r=∛64

r=4

we need to find ar and ar²

ar=9*4

ar=36

ar²=9*4²

ar²=144

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