Chemistry, asked by dharanisri1118, 11 months ago

instrumentation of FTIR​

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Answered by prashik1kamble
6

Answer:

The source energy strikes the beamsplitter and produces two beams of roughly the same intensity. One beam strikes the fixed mirror and returns to the beamsplitter. The other beam goes to the moving mirror. The motion of the moving mirror makes the total pathlength variable versus that taken by the fixed mirror beam. When these two beams meet up again at the beamsplitter, they recombine, and the difference in their path lengths create constructive and destructive interference, an interferogram.

The recombined beam passes through the sample. The sample absorbs all the wavelengths characteristic of the its spectrum and then subtracts specific wavelengths from the interferogram. The detector now reports variation in energy-versus-time for all wavelengths simultaneously. A laser beam is superimposed to provide a reference for the operation of the instrument.

A mathematical function known as a Fourier transform is used to convert the intensity-versus-time spectrum into an intensity-versus-frequency spectrum.

Answered by Anonymous
46

Answer:

Explanation:

See in the attachment

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