Math, asked by srivarshith5599, 6 months ago

int(3cos x+2sin x)/(4sin x+5cos x)dx= 1) (23/41)x-(2/41)log|4sin x+5cos x|+c 2) (23/41)x+(2/41)log|4sin x+5cos x|+c 3) (2/41)x+(23/41)log|4sin x+5cos x|+c 4) (2/41)x-(23/41)log|4sin x-5cos x|+c​

Answers

Answered by sadyboy
0

Step-by-step explanation:

int(3cos x+2sin x)/(4sin x+5cos x)dx= 1) (23/41)x-(2/41)log|4sin x+5cos x|+c 2) (23/41)x+(2/41)log|4sin x+5cos x|+c 3) (2/41)x+(23/41)log|4sin x+5cos x|+c 4) (2/41)x-(23/41)log|4sin x-5cos x|+c

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