Question

int a=1;int sign= 1; int b=0;​

Answer 1

Explanation:

#include <stdio.h>

int main()

{

int a =1 ;

int sign =1 ;

int b =0 ;

for( int i=1;i<=4;i++)

{

 for(int j =i ;j>= 1;j--)

 {

   a = a+b;

 b++;

 

 printf("%d",a*sign);

 sign=sign* -1;

 }

 printf("\n");

}

}

Output:

1

-24

-711-16

22-2937-46