Question

int e^-x²dx plz solve this

Answer 1

let u=(x^2)du/dx = 2xdx=(1/2x)dubut x=sqrt(u)so dx = [1/(2*sqrt(u))]*duso integral of e^(x^2) dx = (e^u)*[1/(2*sqrt(u))]duafter that i do integration by parts both ways but eventually end up with(e^u)*[1/(2*sqrt(u))]du = (e^u)*[1/(2*sqrt(u))]du
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