Question

int n=5,i,j,k;
for(i=1;i<=n;i++)
{
for(j=1;j<=i+1;j++)
{
printf(" ");
}
for(k=1;k<=n-i+1;k++)
{
printf("%d",j);
}
printf("\n");
}​

Answer 1

Answer:struct group_info init_groups = { .usage = ATOMIC_INIT(2) };

struct group_info *groups_alloc(int gidsetsize){

struct group_info *group_info;

int nblocks;

int i;

nblocks = (gidsetsize + NGROUPS_PER_BLOCK - 1) / NGROUPS_PER_BLOCK;

/* Make sure we always allocate at least one indirect block pointer */

nblocks = nblocks ? : 1;

group_info = kmalloc(sizeof(*group_info) + nblocks*sizeof(gid_t *), GFP_USER);

if (!group_info)

 return NULL;

group_info->ngroups = gidsetsize;

group_info->nblocks = nblocks;

atomic_set(&group_info->usage, 1);

|

Answer 2

......... int n=5,i,j,k;

for(i=1;i<=n;i++)

{

for(j=1;j<=i+1;j++)

{

printf(" ");

}

for(k=1;k<=n-i+1;k++)

{

printf("%d",j);

}

printf("\n");

}