Question

integeration of e^tan^-1x​

Answer 1

Step-by-step explanation:

Let

y=tan^-1x

diffrentiate w.r.t x,

y1=1/(1+x^2)1/(x^2-i^2){(x-i)(x+I)}......

{i.^2}

By partial fraction

y=1=1/2i[1(x-1)-1/(x+I)]

equation 1

[note:if yn=(-1)^nn! a^n(ax+b)^(n+1)]