Question

integeration of (log x)2 dx is​

Answer 1

$\int\limits {2(logx)} \, dx\\\\\int\limits{2.logx} \, dx\\\\rule\\\int\limits{u.v} \, dx = u\int\limits{v} \, dx - \int\limits{[\frac{du}{dx} } \,\int\limits{v} \, dx]dx$

$logx\int\limits{2} \, dx-\int\[[\frac{d logx}{dx} } \,\int\limits{2} \, dx]dx\\\\2xlogx - \int\limits{\frac{1}{x} } \, 2x dx \\\\2xlogx-\int\limits{2} \, dx\\\\2xlogx-2x\\\\2x(logx-1)$