integral(1+tan^3(x)).sec^2(x) dx
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12th
Maths
Integrals
Integration by Substitution
∫tan3 2x sec 2x dx
MATHS
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Asked on December 20, 2019 by
Rythm Potnuru
∫tan
3
2xsec2xdx
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ANSWER
LetI=∫tan
3
2x.sec2xdx
=∫tan
2
2x.sec2x.tan2xdx
=∫(sec
2
2x−1)sec2x.tan2xdx
Put sec2x=t
2sec2x.tan2xdx=dt
Now sec2x.tan2xdx=
2
dt
I=
2
1
∫(t
2
−1)dt
=
2
1
[
3
t
3
−t]+C
=
2
1
[
3
sec
3
2x
−sec2x]+C
Step-by-step explanation:
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