Question

integral dt/t pls help​

Answer 1

Hope this helps

In case the last sentence isn't visible, it says

"We put t in modulus since log of -ve is not defined"

Edit: Oh and it will be logₑ|t| + C

(I forgot to add the C)

Answer 2

$\displaystyle \sf \int\limits_{}^{} \: \frac{dt}{t} = log \: |t| + c$

Given :

The integral

$\displaystyle \sf \int\limits_{}^{} \: \frac{dt}{t}$

To find :

To integrate

Solution :

Step 1 of 2 :

Write down the given Integral

The given Integral is

$\displaystyle \sf \int\limits_{}^{} \: \frac{dt}{t}$

Step 2 of 2 :

Integrate the integral

$\displaystyle \sf \int\limits_{}^{} \: \frac{dt}{t}$

$\displaystyle \sf = \int\limits_{}^{} \: \frac{1}{t} \: dt$

$\displaystyle \sf = log \: |t| + c$

Where c is integration constant

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