Math, asked by tanapalsweekarre, 1 year ago

Integral dx by cosec4x - cot4x

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Answered by rohitkumargupta
26

\bf \: HELLO \: \: DEAR,<br /><br /><br /> \\  \\ \bf \int \frac{dx}{cosex4x - cot4x}<br /><br />\\ \\ \bf \int \frac{dx}{cosec4x - cot4x} * \frac{cosec4x + cot4x}{cosec4x + cot4x}<br /><br /><br /> \\  \\  \\ \bf \int \frac{dx(cosec4x + cot4x)}{(cosec^{2}4x - cot^{2}4x) }<br /> \\  \:  \:  \:  \:  \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:  \therefore \boxed{\bf cosec^{2}A - cot^{2}A = 1}<br /><br /> \\  \\  \\ \bf \int cosec4x. dx + \int cot4x .dx<br /><br /> \\  \\  \\ \bf \frac{1}{4} log|cosec4x - cot4x| + \frac{1}{4} log|sin4x| + c<br /><br /> \\  \\  \\ \underline{\bf I \: \: HOPE \: \: ITS \: \: HELP \: \: YOU \: \: DEAR, \: \: <br />THANKS}
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