Integral factor of xy (1 + xy2) dy/dx=1
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Answered by
3
Answer:
1x+xy3/3
Step-by-step explanation:
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Answered by
1
Answer:
25(2x+y)^2-16(x-y)^2[5(2x+y)]^2-[4(x-y)]^2
using identity a^2-b^2=(a+b)(a-b)
[5(2x+y)+4(x-y)] [5(2x+y)-4(x-y]
[10x+5y+4x-4y][10x+5y-4x+4y]
(14x-y)(6x+9y)
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