Question

Integral log√x/3x dx​

Answer 1

Answer:

I=∫

3x

log

x

dx=∫

3x

logx

2

1

dx=∫

3x

2

1

logx

dx=

6

1

∫

x

logx

dx

=

6

1

∫logxd(logx)=

6

1

2

(logx)

2

+c=

3

1

(

2

1

logx)

2

+c=

3

1

(log

x

)

2

Answer 2

Answer:

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