Question

integral of square root 1+cos theta​

Answer 1

integral of  root 1 + cos theta= integral of root 1 + integral of cos theta

= root 1 + sin theta

Answer 2

Answer:

2√2[sin(@/2)] + C

Step-by-step explanation:

$(√(1+cos@)) =

= $[√(1+(cos^2(@/2) - sin^2(@/2))]

=$[√(1- sin^2(@/2))+cos^2(@/2)

= $ √[cos^2(@/2) +cos^2(@/2)]

= $ [√ 2cos^2(@/2)]

= √2 $[cos(@/2)]

= 2√2[sin(@/2)] + C