Math, asked by 5403ritu, 8 months ago

integral(sin^2xcos^4x dx)​

Answers

Answered by rsingh625
0

Step-by-step explanation:

s

i

n

2

(

x

)

c

o

s

4

(

x

)

d

x

∫sin2(x)cos4(x)dx

=

1

8

(

1

c

o

s

(

2

x

)

)

(

1

+

c

o

s

(

2

x

)

)

2

d

x

=18∫(1−cos(2x))(1+cos(2x))2dx

=

1

8

(

1

c

o

s

2

(

2

x

)

)

(

1

+

c

o

s

(

2

x

)

)

d

x

=18∫(1−cos2(2x))(1+cos(2x))dx

=

1

8

s

i

n

2

(

2

x

)

d

x

+

1

8

s

i

n

2

(

2

x

)

c

o

s

(

2

x

)

d

x

=18∫sin2(2x)dx+18∫sin2(2x)cos(2x)dx

=

1

16

(

1

c

o

s

(

4

x

)

)

d

x

+

1

48

s

i

n

3

(

2

x

)

=116∫(1−cos(4x))dx+148sin3(2x)

=

1

16

x

1

64

s

i

n

(

4

x

)

+

1

48

s

i

n

3

(

2

x

)

+

C

=116x−164sin(4x)+148sin3(2x)+C

Answered by manu9035
12

Answer:

hope it's correct i m not sure

Step-by-step explanation:

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