Question

integral (sinπ/x)(1/x^2)​

Answer 1

Answer:

1/π cos(π/x)

Step-by-step explanation:

given ∫ sin (π/x)*(1/x²) dx

let 1/x = u

    -1/x² dx = du

applying these

∫ -sin (uπ) du

= 1/π cos(uπ)

apply the value of u

= 1/π cos(π/x)