area of the shaded region. (Use t = 3.14)
(CBSE 2019
D
А
C
B
Fig. 13.113
55. In Fig. 13.113, ABCD is a square with side 22 cm and inscribed in a circle. Find the
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Answer:
BD2 = (2√2)2 + (2√2)2
BD2 = 16
BD = 4 cm
∴ Radius of circle = 2 cm
∴ Shaded area = Area of circle – Area of square
= 3.14 × 22 − (2√2)2
= 12.56 – 8
= 4.56 cm2
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