Question

Integral sin2xcos3x dx

How can you solve this

Answer 1

For solving this, let's consider the formula sin(A+B)+sin(A-B) = 2sinAcosB

=> sin2xcos3x = 1/2(sin5x-sinx)

=> int sin2xcos3x dx = int 1/2(sin5x-sinx) dx

=> 1/2{(-cos5x)/5 + cosx} + C

=> {(cosx)/2} - {(cos5x)/10} + C

Hope this helps.... Have a great day ahead....