The sum of the digits of a 2-digit number is 12. The number obtained by interchanging its digits is 18 more than the original number. Find the original number.
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Answered by
2
Answer:
Let the tens digit of the required number be x and the units digit be y. Then,
x+y=12 .........(1)
Required Number = (10x+y).
Number obtained on reversing the digits = (10y+x).
Therefore,
(10y+x)−(10x+y)=18
9y−9x=18
y−x=2 ..........(2)
On adding (1) and (2), we get,
2y=14⟹y=7
Therefore,
x=5
Hence, the required number is 57.
Answered by
2
Answer:
Original number =57
Step-by-step explanation:
Let the original number be 10x +y
By the given information
x+y =12
Let the interchanged number be 10y+x
Accordingly
10x +y = 18 + 10y + x
On solving the equation, we get
x = 5 and y =7
Thus the number is 57
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