Question

integral sin4x value lies pi/4 to 0​

Answer 1

Answer:

$\int \sin4x \\ = - \cos4x. \frac{4 {x}^{2} }{2} + c \\ = 2 {x}^{2} .( - \cos4x) + c \\ \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \blue{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$