integral x^2/(x^2+1)(x^2+4)dx
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129Raj:
Sin^(-1) [(2x+1)/5]
sorry brother , solve it
not only answer
ok
Solve it By partial fraction method
sorry
i.e. wrong method
Put. √(6-x-x²). = √[6+1/4 -(x²+x+1/4)]
Then it is in perfect square
=√[(5/2)² - (x+1/2)²]. Then i.e. is in the format of some special integral. √(a²-x²)
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