Question

integral z^2-4/z^2+4
d z. Evaluated anticlockwise around the circle (z-i)=2 is -
$integral \frac{ {z}^{2} - 4}{ {z}^{2} + 4} dz.evaluated \: anticlockwise \: around \: the \: circle |z - i| = 2 \: is$
​

Answer 1

Answer:

-4pi

Step-by-step explanation: