Question

integrate 1/v²

ans fast​

Answer 1

Hey mate,

We know,

1/v^2 = v^-2

Now we know,

Integration of x^y = x^y+1/y+1

So,

Apllying the property of integration,

= v^-2+1/-2+1

= v^-1/-1

= - 1/v

Hope this helps you out!

Answer 2

-1/v is correct answer.......