Question

integrate (2 – 3x)(3+2x)(1–2x) dx​

Answer 1

Step-by-step explanation:

(2-3x)(3+2x)(1-2x)

=(6+4x-9x-6x^2) (1-2x)

=(6-5x-6x^2)(1-2x)

=(6-12x-5x+10x^2-6x^2+12x^3)

=(6-17x+4x^2+12x^3)

integrating above w.r.t x

(6x)-{(17x^2)/2}+{(4x^3)/3} + (3x^4)