Question

integrate
(2x-3)sin²x dx​

Answer 1

Answer:

∫sin(2x)dx

Make a substitution u=2x

du=2dx

∫sin(2x)dx=12∫sin(u)du

=−12cos(u)+c=−12cos(2x)+c

However, this is related to sin2(x)by the identity sin2(x)=1−cos(2x)2

Step-by-step explanation:

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