integrate 2y-4(y+1)=16
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Answered by
1
2y-4y-4=16
-2y=20
y=-10
-2y=20
y=-10
Answered by
1
Heya.........
here's your answer......
2y - 4 ( y + 1 ) = 16
2y - 4y - 4 = 16
-2y - 4 = 16
-2y = 16 + 4
-2y = 20
y = -20 / 2
y = -10
hope it will help you
here's your answer......
2y - 4 ( y + 1 ) = 16
2y - 4y - 4 = 16
-2y - 4 = 16
-2y = 16 + 4
-2y = 20
y = -20 / 2
y = -10
hope it will help you
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