Math, asked by prashant1421, 1 year ago

integrate
3x-1/(x-1)(x-2)(x-3)

Answers

Answered by Ben193
1
hey!
the answer is,
3x-1/(x-1)(x-2)(x-3)
= 3x-1/(x^2-2x-x+2)×(x-3)
= 3x-1/(x^2-3x+2)×(x-3)
= 3x-1/x^3-3x^2-3x^2+9x+2x-6
= 3x-1/x^3-6x^2+11x-6
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