integrate 3x.sinx dx
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Now, ∫ 3x sinx dx
= 3x ∫ sinx dx - ∫ { d/dx (3x) ∫ sinx dx } dx + c,
where c is integral constant
= - 3x cosx + 3 ∫ cosx dx + c
= - 3x cosx + 3 sinx + c
Hope it helps! (:
Now, ∫ 3x sinx dx
= 3x ∫ sinx dx - ∫ { d/dx (3x) ∫ sinx dx } dx + c,
where c is integral constant
= - 3x cosx + 3 ∫ cosx dx + c
= - 3x cosx + 3 sinx + c
Hope it helps! (:
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